Answer:
The molarity of this NaCL solution is 1.83 M:
Explication:
Step 1: Data given
Mass of NaCl = 24.4 grams
Mass of water = 251 grams
Density of water = 1.10 g/mL
Step 2: Calculate volume of water
Volume of water = Mass of water / density of water
Volume of water = 251 grams / 1.10 g/mL
Volume of water = 228.18 mL =0.22818L
Step 3: Calculate moles NaCl
Number of moles NaCl = 24.4 grams / 58.44 g/mol
Number of moles = 0.4175 moles
Step 4: Molarity of the solution
Molarity = Number of moles / Volume
Molarity = 0.4175 moles / 0.22818 L
Molarity = 1.83 M
The molarity of this NaCL solution is 1.83 M