Answer:
$11.50
Step-by-step explanation:
Let R = Revenue function = Price of ticket × booked seats
Let n = number of times lowered the price of ticket by $1.
Price = ($12 - n × $1) = 12 - n dollars
Quantity = number of sold tickets (1100) + n (1000) = 11,000 + 1,000n spectators
Therefore, R(n) = (12-n) (11000 + 1000n) = 132,000 + 1000n - 1000n²
= -1000 (x² - x - 132)
= -1000 ((x - 1/2)² - 529/4)
= -1000 (x - 1/2)² + 132,250
R(n) - 13,250 = -1,000 (x - 1/2)²
n = 0.5 ⇒ 12 - 0.5 = $11.50
Spectators = 11,000 + 1,000 (1/2) = 11,500
Revenue = $13,250
They should set their price at $11.50 for maximum revenue.