Answer:
Maximum area = 98
Step-by-step explanation:
Fencing available = 28 yards
Let l be the length and w be the width of rectangular garden,
We have fencing in 3 sides 3 sides
That is
Fencing needed = 2l + w = 28
w = 28 - 2l
Area of rectangle = l x w = l x (28 -2l) = 28l-2l²
For maximum area we have,
[tex]\frac{dA}{dl}=0\\\\\frac{d}{dl}\left ( 28l-2l^2\right )=0\\\\28-4l=0\\\\l=7yards[/tex]
We have
2l + w = 28
2 x 7 + w = 28
w = 14 yards
Maximum area = 7 x 14 = 98 yard²
Maximum area = 98