Question

what are the solutions to the equation x2 +3x-4=0

Answer 1

$x^{2} +3x-4=0$

You wan't to get it into a format of (x+a)(x+b)=0
where a+b = 3 (the one from the 3x)
and where a*b= -4 (from the last -4)

(x+4)(x-1)=0
See how 4+(-1) = 3 and (4)(-1) = -4

now find what values of x would make the equation equal 0
x=-4
(-4+4)(-4-1) = (0)(-5) = 0

x=1
(1+4)(1-1) = (5)(0) = 0

Answer 2

x^2+3x-4=0
(x-1)(x+4)=0
x-1=0 x+4=0
x=1 x=-4
The solutions are 1 and -4.