Question

What is the equation for the line that passes through points (4, –1) and (–4, 3)?
a. b.
c. d.

Answer 1

Hello,

y+1=(3+1)/(-4-4)*(x-4)
==>y=-x/2+1
or x+2y=2
or x+2y-2=0

Answer 2

y=mx+b
m=slope
b=yitercept

slope for 2 points (x1,y1) and (x2,y2)
slope=(y2-y1)/(x2-x1)

bettween (4,-1) and (-4,3)
slope=(3-(-1))/(-4-4)=(3+1)/-8=4/-8=-1/2
slope=-1/2

y=-1/2x+b
sub apoint and solve

(x,y)
(4,-1)
if x=4, y=-1
-1=-1/2(4)+b
-1=-2+b
add 2
1=b

y=-1/2x+1