Question

An engineer on the ground is looking at the top of a building the angle of elevation to the top of the building is 22 degrees the engineer knows the building is 450 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?

Answer 1

Hello,

tan 22°=450/d
==>d=450/tan 22°=1113.7890... ≈1114 (ft)

Answer 2

Answer:

1114 foot

Step-by-step explanation:

Let the engineer is at a distance of x feet from the base of the building.

Please see the attached image.

In the triangle, we have

$\tan22^{\circ}=\frac{450}{x}$

Solving the equation for x, we get

$x=\frac{450}{\tan22^{\circ}}\\\\x\approx1114$

Thus, the engineer is 1114 foot from the base of the building.