Question

Consider the reaction: Na2CO3 + 2HCl → 2NaCl + CO2 + H2O. A minimum of _____ moles of sodium carbonate is needed to fully react with 750 g of HCl

Answer 1

Na₂CO₃ + 2 HCl  = 2 NaCl + CO₂ + H₂O

106 g Na₂CO₃ -------- 2 x 36.5 g HCl
 x g Na₂CO₃ ---------- 750 g HCl

Mass of Na₂CO₃ = 750 x 106 / 2 x 36.5

Mass ( Na₂CO₃) = 79500 / 73

Mass = 1089.04 g

Number of moles = 1089.04 / 106 => 10.27 mols of Na₂CO₃

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