Respuesta :
Answer:
The correct option is 3.
Step-by-step explanation:
The first and third quartile of the data are 13 and 37.
The interquartile range is the difference between Q₃ and Q₁.
[tex]\text{Interquartile Range}=Q_3-Q_1[/tex]
[tex]\text{Interquartile Range}=37-13=24[/tex]
We have to find 1.5 (IQR),
[tex]1.5\times \text{Interquartile Range}=1.5\times 24=36[/tex]
Now subtract 36 from Q₁ and add 36 in Q₃, if data lies outside the interval [Q₁-1.5(IQR),Q₃+1.5(IQR)] are called outliers.
[tex]Q_1-36=13-36=-23[/tex]
[tex]Q_3+36=37+36=73[/tex]
The outliers are the numbers which lies outside the range [-23,73]. Only 78 lies outside the range, therefore the correct option is 3.
Answer:
its C The greatest value, 78, is the only outlier
Step-by-step explanation: