Hello,
gravity on earth :g=9.81 m/s²
[tex] h(t)=-\frac{g*t^2}{2}+v_{0}*t+h_{0}[/tex]
9.81/2≈4.9
[tex] v_{0}\ is\ initial\ speed[/tex]
[tex] h_{0}\ is\ initial\ height[/tex]
Answer 1
2)
h(t)=-4.9*t²+20*t+10
To hit the ground ht(t)=0
==> -4.9*t²+20*t+10=0
Δ=20²+4*4*10=560=23,6643...²
t=(-20-4√35)/(-4.9*2)=4,4555...(s)
t=(-20+4√35)/(-2*4.9)=-0,37391... to exclude (time must be >0)