Simplify square root of 5 multiplied by the cube root of 5.

5 to the power of 5 over 6
5 to the power of 1 over 6
5 to the power of 2 over 3
5 to the power of 7 over 6

Respuesta :

Answer:

5 to the power of 5 over 6 = [tex]5^{\frac{5}{6}}[/tex]

Step-by-step explanation:

1)Let's define some properties about exponent:

[tex]a^{\frac{b}{c}}=\sqrt[c]{a^{b}}[/tex]

For example :

[tex]4^{\frac{1}{2}}=\sqrt[2]{4^{1}}=\sqrt[2]{4}=\sqrt{4}=2[/tex]

[tex]2^{\frac{6}{3}}=\sqrt[3]{2^{6}}=\sqrt[3]{64}=4[/tex]

2)Another property of exponent is :

[tex](a^{b}).(a^{c})=a^{b+c}[/tex]

For example :

[tex](4^{2}).(4^{3})=4^{2+3}=4^{5}=1024[/tex]

This means that when we have two exponential functions with the same base that are multiplying between them, we can sum the exponents in order to make a new exponential function with the same base.

Using this two properties we can solve the problem.

  • The expression is:

[tex](\sqrt{5}).(\sqrt[3]{5})[/tex]

  • Using the two properties :

[tex](\sqrt{5}).(\sqrt[3]{5})=(5^{\frac{1}{2}}).(5^{\frac{1}{3}})=5^{\frac{1}{2}+\frac{1}{3}}[/tex]

Now, [tex]\frac{1}{2}+\frac{1}{3}=\frac{5}{6}[/tex]

Therefore, the final expression is

[tex]5^{\frac{1}{2}+\frac{1}{3}}=5^{\frac{5}{6}}[/tex] ⇒

[tex](\sqrt{5}).(\sqrt[3]{5})=5^{\frac{5}{6}}[/tex]

The correct answer is :

5 to the power of 5 over 6.

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