Question

Determine the volume of 2.00 M HCl(aq) solution required to completely neutralize 20.0 milliliters of 1.00 M NaOH(aq) solution.

Answer 1

Molarity is equal to the moles of solute over liters of solvent. In getting the molarity of HCl, you must know the formula for two solutions which is equal to M1V1 = M2V2.  (2.00 M HCl)V1 = (20.0 milliliters) (1.00 M NaOH) and you have the volume of 10 millimeters of HCl.

Answer 2

The volume of the HCl solution required to neutralize 20 mL of 1.00 M NaOH is 10 mL

Balanced equation

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

• The mole ratio of the acid, HCl (nA) = 1
• The mole ratio of the base, NaOH (nB) = 1

From the question given above, the following data were obtained:

• Volume of base, NaOH (Vb) = 20 mL
• Concentration of base, NaOH (Cb) = 1 M
• Concentration of acid, HCl (Ca) = 2 M
• Volume of acid, HCl (Va) =?

CaVa / CbVb = nA / nB

(2 × Va) / (1 × 20) = 1

(2 × Va / 20  = 1

Cross multiply

2 × Va  = 20

Divide both side by 2

Va = 20 / 2

Va = 10 mL

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