[tex]\boxed{x>3/8}[/tex]
The absolute value of a number is a non-negative real number. For example, suppose you have a real number [tex]x[/tex] that can be either positive or negative, that is:
[tex]x\in\mathbb{R}[/tex]
The absolute value of this number is its positive value, that is, if that number is negative, you remove the sign "-".
To show the absolute value of a numbers we put it between bars as follows:
[tex]\mid x \mid[/tex]
In this case, we need the absolute value of -3/8:
[tex]\mid -3/8 \mid[/tex]
[tex]\mid -3/8 \mid = 3/8[/tex]
So the question is which number is greater than the absolute value of -3/8?
It is obvious that the numbers greater than the absolute value of -3/8 are those numbers greater than 3/8. In a mathematical language, this can be expressed as:
[tex]\boxed{x>3/8}[/tex]
Inequalities: https://brainly.com/question/12890742
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