Question

At one store a trophy costs $12.50. Engraving costs 0.40 $ per letter. At another store, the same trophy cost $14.75. Engraving costs 0. $.25. How many letters, E, must be engraved for the cost to be the same?

Answer 1

Hence, 15 letters must be engraved for the cost to be same

Further explanation:

We have to make expressions for both shops

So,

Let x be the number of letters

For shop 1:

$12.50 will be absolute

The expression will be:

$12.50+ 0.4x$

For Shop 2 :

The Expression will be:

$14.75+0.25x$

To find the number of letters at which the cost will be same we have to put both expressions equivalent

$12.50+0.4x=14.75+0.25x$

Subtracting 12.50 from both sides

$12.50+0.4x-12.50= 0.25x +14.75-12.50\\0.4x=2.25+0.25x$

Subtracting 0.25x from both sides

$0.4x- 0.25x= 2.25+0.25x-0.25x\\0.15x=2.25$

Dividing both sides by 0.15

$\frac{0.15x}{0.15}=\frac{2.25}{0.15}\\x=15$

Hence, 15 letters must be engraved for the cost to be same

Keywords: Linear equations, costing

Learn more about linear equations at:

• brainly.com/question/2821386
• brainly.com/question/2860697

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