Respuesta :

The image formed from the lens is real, inverted and enlarged

Explanation:

The magnification of a lens is given by:

[tex]m=\frac{y'}{y}=-\frac{q}{p}[/tex] (1)

where:

y' is the size of the image

y is the size of the object

q is the distance of the image from the lens

p is the distance of the object from the lens

For this lens, the magnification is

m = -1.6

We notice the following:

- The magnification is negative

- The magnification is larger than 1

Looking at eq.(1), we can therefore make the following conclusions:

- SInce [tex]m=\frac{y'}{y}[/tex] and [tex]|m|>1[/tex], it follows that [tex]|y'|>|y|[/tex], so the image is larger than the object

- Since [tex]m=\frac{y'}{y}[/tex] and [tex]m<0[/tex], it follows that [tex]y'<0[/tex] (since y > 0 for convention): this means that the image is inverted

- Since [tex]m=-\frac{q}{p}[/tex] and [tex]m<0[/tex], it follows that [tex]q>0[/tex] (since p > 0 for convention): this means that the image is real

Learn more about lenses and mirrors here:

https://brainly.com/question/8737441

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Answer: the image is larger than the object and is real.

Explanation: