Respuesta :
The image formed from the lens is real, inverted and enlarged
Explanation:
The magnification of a lens is given by:
[tex]m=\frac{y'}{y}=-\frac{q}{p}[/tex] (1)
where:
y' is the size of the image
y is the size of the object
q is the distance of the image from the lens
p is the distance of the object from the lens
For this lens, the magnification is
m = -1.6
We notice the following:
- The magnification is negative
- The magnification is larger than 1
Looking at eq.(1), we can therefore make the following conclusions:
- SInce [tex]m=\frac{y'}{y}[/tex] and [tex]|m|>1[/tex], it follows that [tex]|y'|>|y|[/tex], so the image is larger than the object
- Since [tex]m=\frac{y'}{y}[/tex] and [tex]m<0[/tex], it follows that [tex]y'<0[/tex] (since y > 0 for convention): this means that the image is inverted
- Since [tex]m=-\frac{q}{p}[/tex] and [tex]m<0[/tex], it follows that [tex]q>0[/tex] (since p > 0 for convention): this means that the image is real
Learn more about lenses and mirrors here:
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Answer: the image is larger than the object and is real.
Explanation: