Question

Imagine you have a toy box that holds 3 wind-up toys and 5 spinning toys. A toy is taken out of the box and then put back 8 times. A spinning toy is taken out of the box 3 times. What is the experimental probability of drawing a wind-up toy out of the box?

Answer 1

Answer:

\$\frac {3}{5}$

Step-by-step explanation:

The toy box holds 3 wind-up toys and 5 spinning toys. A toy is taken out of the box and then put back 8 times. It will have no effect.

Next, a spinning toy is taken out of the box 3 times. So, there are now

3 wind-up and $(5 - 3) = 2$  spinning toys.

P(Drawing a wind - up toy out of the box)

= $\frac {3}{3 + 2}$

=\$\frac {3}{5}$ (Answer)

Answer 2

Answer: 5/8

You need to find the probability of getting a wind up toy, 8-3 is 5 so then the fractions 5/8