gjp051207
gjp051207 gjp051207
  • 03-11-2019
  • Mathematics
contestada

The points (8,-16) and (6,-14) fall on a particular line. What is its equation in slope-intercept form?​

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cinderofsoulsss
cinderofsoulsss cinderofsoulsss
  • 03-11-2019

Answer:

y = -x - 8

Step-by-step explanation:

First, calculate the slope:

m = [tex]\frac{y2-y1}{x2-x1}[/tex]

(x₁, y₁) will be (8, -16)

(x₂, y₂) will be (6, -14)

Plug in values:

m = [tex]\frac{-14 - -16}{6-8}[/tex]

simplify:

m = [tex]\frac{2}{-2}[/tex]

m = -1

plug values into y = mx + b:

-16 = (-1)(8) + b

solve for b:

b - 8 = -16

b = -8

rewrite the equation:

y = -1x - 8

y = -x - 8

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profarouk profarouk
  • 03-11-2019

Good morning,

Answer:

y = -x - 8

Step-by-step explanation:

look at the photo below for the details.

:)

Ver imagen profarouk
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