Question

Find the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the gas is made to go through isochoric heating until 5460 J of heat is transferred into the gas and its pressure is 3.72 ✕ 105 Pa. In the second step it is subjected to isobaric compression until its volume decreases by 7.50 ✕ 10−3 m3 and 1220 J of heat is transferred out of the gas. What is the total change in internal energy of this gas?______ J?

Answer 1

Answer:

$\Delta V = 5666.8J$

Explanation:

We need to divide the entire process into two different sections, as well

For process 1 we define the following,

It is an Isochoric heating process,

Where $w_1=0 , \Delta V_1 = \Delta H_1 = 5060J$

On the other hand for process 2

It is an Isobaric compression process,

Where $w_2 = P \Delta V$

$\Delta V_2 = \Delta H_2  w_2$

$\Delta V_2 = -1270 - 2.75*10^5 (-6.9*10^{-3})$

$\Delta V_2 = 606.8J$

Thus,

$\Delta V = \Delta V_1 + \Delta V_2$

$\Delta V = 5666.8J$