Answer:
The correct answer to the following question is h = 8.
Explanation:
Because size of the network part always either be 8, 16, or 24 bits, it is based on whether it is the Class A, B, or C. As the Class A addresses, N=8. Mask 255.255.255.0, which is converted to the prefix format, is 24. The number of sub-net bits is difference between prefix length is (24) and the N, so, S = 16 in the case. Size of host part is the number when it added to prefix length which is (24) then, it give you 32.
so that's why H=8 in this case.