Question

The position of an object moving in a straight line is given by the following formula where s is in meters and t is the time in seconds the object has been in motion. f[ s = 2t^2 - 3tf] How long (to the nearest tenth) will it take the object to move 9 meters?

Answer 1

Answer:

3 s

Explanation:

s = 2t^2 - 3t

s = 9 m

$9 = 2t^{2}-3t$

$2t^{2}-3t-9=0$

$2t^{2}-6t+3t-9=0$

$2t(t-3)+3(t-3)=0$

(t - 3)(2t + 3) = 0

time cannot be negative, so t = 3 s

Thus, the object takes 3 second to move 9 m.