Answer:
Step-by-step explanation:
Given that the chocolate factory "Charlie’s own" produces limited-time boxes with exactly 9 chocolates.
X is the weight of chocolate
X is N (5, 0.3) (since variance = 0.09, std dev =sqrt of variance = 0.3)
Probability for the box to weight <42.75 =
P(X<42.75)
=[tex]P(Z<\frac{42.75-5(9)}{3(0.3)} =P(Z<-2.5)\\=0.5-0.4938\\=0.0062[/tex]
Or 0.62% of boxed weigh <42.75
[tex]\phi = -2.5[/tex]