Answer: 85 percent
Explanation:
we are given
mass = 200.4 kg
weight = 200 N
force = 75 N
distance = 10 m
height = 3 m
velocity = 2 m/s
the efficiency of a sled on a slope η = output power (Po) / input power (Pi)
Po = Increase in potential energy of the sled + Increase in kinetic energy of the sled
Po = mgh + (1/2)mv^2
where m = mass
g = acceleration due to gravity
h = height
v = velocity
and Pi = energy expended = force (F) x distance (d)
therefore efficiency = ( mgh + (1/2)mv^2 ) / ( F x d )
efficiency = ( ( 20.4 x 9.8 x 3 ) + (1/2) x 20.4 x 2^2 ) / ( 75 x 10 )
efficiency = 0.8544 = 85 percent
