Question

An element with mass 290 grams decays by 13.2% per minute. How much of the
element is remaining after 14 minutes, to the nearest 10th of a gram?​

Answer 1

Answer:

FV=PV(1−d)^n

FV = 290(1-.132)^14

FV = 290(.868)^14

FV = 39.96 g

Step-by-step explanation:

Answer 2

Answer:

40.0 grams

Step-by-step explanation:

An exponential decay function is

$y=a(1-r)^t$           .... (1)

where, a is initial value, t is time and r is decay rate.

It is given that element with mass 290 grams decays by 13.2% per minute.

Initial value = 290

Decay rate = 13.2% = 0.132

Substitute a=290 and r=0.132 in equation (1).

$y=290(1-0.132)^t$  

$y=290(0.868)^t$  

Substitute t=14 to find the amount of element remaining after 14 minutes.

$y=290(0.868)^{14}$  

$y=39.9644785$  

Round the solution to the nearest tenth.

$y\approx 40.0$  

Therefore, element with mass 40.0 grams is remaining after 14 minutes.