Answer:
$4,603.82
Step-by-step explanation:
A new car is purchased for 20,000 dollars,
P = $20,000
The value of the car depreciates at 12.5%,
r = 1 - 0.125 = 0.875
I = value of the car after
t = 11 years
Use formula
[tex]I=P\cdot r^t[/tex]
Hence,
[tex]I=\$20,000\cdot 0.875^{11}\\ \\I=\$4,603.82[/tex]