Answer:
3
Step-by-step explanation:
This is very easily solved by picking a number for x and solving.
We need a number (x) that leaves a remainder of 4 when divided by x.
Let's start with 7 * 1 = 7
7 divided by 7 leaves a remainder of 0
So, 7 + 4 = 11 divided by 7 would leave a remainder 4.
Thus, our integer (x) is 11
Now, what is [tex]x^2+2x[/tex]? When x = 11, this is
[tex]x^2+2x=(11)^2+2(11)=143[/tex]
What is 143 divided by 7 with a remainder?
140/7 = 20 (no remainder)
So 143/7 will have "3" as remainder.
Thus, we can conclude the remainder of [tex]x^2+2x[/tex] when divided by 7 will have remainder of 3 no matter the value of x.