Answer:
16.02kW and 12.91kW
Explanation:
Knowing the enthalpy data, we have to
[tex]h1=239.16kJ/kg\\h2=296.81kJ/kg[/tex]
So,
[tex]E_{mass,in}=mh_1[/tex]
Here,
m=mass flow rate
h= Enthalpy of refrigerant at the compressor
Replacing
[tex]E_{mass,in}=(0.054Kg/s)(239.16kJ/kg)\\E_{mass,in}=12.91kW[/tex]
The rate of energy transfer by mass into the compressor is 12.91kW
In the other hand we have,
[tex]E_{mass,out}=mh_2[/tex]
Replacing
[tex]E_{mass,out}=(0.054Kg/s)(296.81kJ/kg)\\E_{mass,out}=16.02kW[/tex]
The rate of energy transfer by mass out of the compressor is 16.02 kW