Question

What is the completely factored form of 2x2 – 32?
(2x2 + 16)(x - 16)
o 2(x+4)(x-4)
2(x + 3)(x – 4)
2(x - 3)(x – 4)

Answer 1

Answer:

The completely factored form of  $2x^{2}  - 32$ =  $2(x+ 4)(x-4)$

Step-by-step explanation:

Here, the given expression is : $2x^{2}  - 32 = 0$

Now, simplifying the given expression , we get

$2x^{2}  - 32$ =  $2(x^{2}  - 16)$

Now, by ALGEBRAIC IDENTITY, we know that

$a^{2} - b^{2}  = (a+b)(a - b)$

So, here $x^{2} - (4)^{2}  = (x+4)(x - 4)$

⇒$2(x^{2}  - 16)$  = $2(x+ 4)(x-4)$

Hence, the completely factored form of  $2x^{2}  - 32$ =  $2(x+ 4)(x-4)$

Answer 2

Answer: 2(x + 4)(x – 4)

Step-by-step explanation: just took the test