Question

A gust of wind blows an apple from a tree. As the apple falls, the force of gravity on the apple is 9.20 N downward, and the force of the wind on the apple is 1.16 M to the right. What is the magnitude of the net external force on the apple

Answer 1

Answer:

9.27 N

Explanation:

There are two forces acting on an apple.

F1 = 9.20 N downwards

F2 = 1.16 N rightwards

these two forces are acting at right angle to each other.

Use the formula of vectors to find the resultant of two forces

$R = \sqrt{A^{2}+B^{2}+2AB Cos\theta }$

According to the question angle is 90°.

So, Resultant of to forces is

$R = \sqrt{9.2^{2}+1.16^{2}+2\times 9.2\times 1.16 Cos90 }$

R = 9.27 N

Thus, the magnitude of the resultant force is 9.27 N.