Question

The hammer throw was one of the earliest Olympic events. In this event, a heavy ball attached to a chain is swung several times in a circular path until it is released. The winning athlete is the one who throws the ball the greatest distance. The last complete rotation of 2016 Olympic champion Anita Włodarczyk’s final turn took only 0.43 s. The radius of the ball’s path, including her extended arms, was 2.1 m. a) What was the frequency of this rotation? b) What was the speed of the ball? c) What was the ball’s acceleration, in units of g?

Answer 1

Answer:

Given that

T= 0.43 s

Radius of the ball path's , r=2.1 m

a)

We know that

f= 1/T

Here f= frequency

      T= Time period

Now by putting the values

f= 1/T

T= 0.43 s

f= 1/0.43

f=2.32 Hz

b)

We know that

V= ω r

ω = 2 π f

ω=Angular speed

V= Linear speed

ω = 2 π f=ω = 2 x π x 2.32 =14.60 rad/s

V= ω r= 14.60 x 2.1 = 30.66 m/s

c)

Acceleration ,a

a =ω ² r

a= 14.6 ² x 2.1 = 447.63 m/s²

We know that g = 10 m/s²

So

a= a/g= 447.63/10 = 44.7 g m/s²

a= 44.7 g m/s²

Answer 2

In this question we are going to calculate the throw of the Olympic Hammer Throwing Championship.

The Olympic Hammer Throwing

In hammer throwing, what is actually thrown is a steel ball attached to a metal handle. “To make the throw, the athlete turns the cable from four to six turns, at maximum speed, and performs the throw”, says the teacher. “This happens in a short period of time, from 5 to 6 seconds, which is the maximum that an athlete can accelerate the weight. From that time on, they cannot accelerate any further.” The distance reached can reach more than 80 meters.

• a)2.32 Hz

• b)30.66 m/s

• c)g = 10 m/s²

V= ω r

ω = 2 π

ω=Angular speed

V= Linear speed

a =ω ² r

With this information, we calculated the throw of the Olympic hammer throwing champion.

Learn more about Olympic Hammer Throwing in brainly.com/question/3212085