Answer:
[tex]v = 339 m/s[/tex]
Explanation:
As we know that the horizontal speed of the plane is always constant
so here the speed in x direction always remain the same and given as
[tex]v_x = 104 m/s[/tex]
now in order to find vertical speed we can use kinematics so we will have
[tex]v_f^2 - v_i^2 = 2a d[/tex]
here we have
[tex]v_f^2 - 0^2 = 2(9.81)(5300)[/tex]
[tex]v_y = 322.5 m/s[/tex]
now net speed at which it will strike is given as
[tex]v = \sqrt{v_x^2 + v_y^2}[/tex]
[tex]v = \sqrt{104^2 + 322.5^2}[/tex]
[tex]v = 339 m/s[/tex]