Answer: Jason has 7 pennies and 6 nickels.
Step-by-step explanation:
Let be "p" the number of pennies that Jason has and "n" the number of nickels that Jason has.
Set up a system of equations:
[tex]\left \{ {p+n=13} \atop {0.01p+0.05n=0.37}} \right.[/tex]
You can use the Elimination Method. Multiply the first equation by -0.01 and add both equations:
[tex]\left \{ {-0.01p-0.01n=-0.13} \atop {0.01p+0.05n=0.37 }} \right.\\................................\\0.04n=0.24\\\\n=6[/tex]
Susbtitute this value into the first equation and solve for "p":
[tex]p+6=13\\\\p=13-6\\\\p=7[/tex]