Question

1. In 1976, Kitty Hambleton of the United States drove a rocket-engine
car to a maximum speed of 965 km/h. Suppose Kitty started at rest
and underwent a constant acceleration with a magnitude of 4.0 m/s2.
What distance would she have had to travel in order to reach the maxi-
mum speed?

Answer 1

Answer: 8981.72 m

Explanation:

We can use the following equation to solve this problem:

$V^{2}=V_{o}^{2} + 2ad$

Where:

$V=965 \frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=268.05 m/s$ is Kitty's final (maximum) speed

$V_{o}=0 m/s$ is Kitty's initial speed (since it started from rest)

$a=4 m/s^{2}$ is the acceleration

$d$ is the traveled distance

Isolating$d$:

$d=\frac{V^{2}-V_{o}^{2}}{2a}$

$d=\frac{(268.05 m/s)^{2}-(0 m/s)^{2}}{2(268.05 m/s)}$

Finally:

$d=8981.72 m$