The larger of two numbers exceeds twice the smaller by one. The system of equations are y = 2x + 1 and y + 6 = 3x. So option 2 is correct
Solution:
Given, y is the larger number and x be the smaller number.
We have to find which of the given systems of equations represents the word problem?
Now, the larger of two numbers exceeds twice the smaller by one.
Then, y – (2 × x) = 1 ⇒ y – 2x = 1 ⇒ y = 2x + 1
And, three times the smaller exceeds the larger by six
Then, 3 × x – y = 6 ⇒ 3x – y = 6 ⇒ y + 6 = 3x
Hence, the system of equations are y = 2x + 1 and y + 6 = 3x. so option 2 is correct.