Respuesta :

at 60ºC NH₄Br(s) :

105 g of NH₄Br in 100 g (H₂O) 

105 g ------------ 100 g
? g --------------- 200.0 g

mass = 200.0 * 105 / 100

mass = 21000 / 100

= 210 g of NH₄Br(s)

hope this helps!

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