Question

You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. The wall is 22.0 m from the release point of the ball. How long does the ball take to reach the wall?

Answer 1

The ball takes about 1.15 seconds to reach the wall

Further explanation

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem!

This problem is about Projectile Motion

Given:

initial speed = u = 25 m/s

angle of speed = θ = 40.0°

horizontal distance = x = 22.0 m

Unknown:

time taken by the ball = t = ?

Solution:

We will use this following formula to find the time taken by the ball to reach the wall:

$x = u_x t$

$x = u \cos \theta ~t$

$22 = 25 \cos 40^o ~t$

$t = 22 \div ( 25 \cos 40^o )$

$t \approx 1.15 \texttt { seconds}$

$\texttt{ }$

Conclusion :

The ball takes about 1.15 seconds to reach the wall

$\texttt{ }$

Learn more

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Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall

Answer 2

The long of ball take to reach the wall is 1.148 second

Explanation:

The velocity is the rate of change of its position with respect to a frame of reference. It is have a function of the time.  

Projectile motion is a form of motion by an object that is thrown near the Earth's surface and moves along a curved path under the action of gravity only. For example, we can throw the ball straight upward, or kick a ball and give it a speed at an angle to the horizontal

You throw a ball with a speed of 25.0 m/s at an angle of 40.0 degrees above the horizontal directly toward a wall. This phenomenon can be seen in the picture below. How long does the ball take to reach the wall?

We don't know about the ball condition, it follows the path 1 or 2. But it doesn't matter because we just want to know about the time it takes the ball to reach the ball.

The horizontal component of the velocity of the ball is:

$V_x = v cos 40$

$V_x = 25 cos 40$

$V_x = 19.151 m/s$

Now, the time taken would be

$t=\frac{R}{V_x} = \frac{22}{19.151} = 1.148 s$

Learn more about speed  

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