Respuesta :
Answer:
∠ R [tex]>[/tex] 90°
[tex]\angle s + \angle T < \angle 90[/tex]
[tex]\angle R > \angle T[/tex]
[tex]\angle R > \angle S[/tex]
Step-by-step explanation:
Given that in triangle RST
[tex]\angle R> (\angle s +\angle T)[/tex]
Now as per condition one angle is greater than sum of other two angles.
Since in triangle ,sum of all three angles = 180°
Hence if one angle is 90° then sum of other two must be equal to 90°
And if one angle is 90° then only other two angle be 45° each
Here Let if angle s = angle T = 30° then with this condition angle r is 120° , which is greater than 90°
So, from above it conclude that
For , [tex]\angle R> (\angle s +\angle T)[/tex]
∵ ∠ R = 120° , then it is greater than 90°
I.e , ∠ R [tex]>[/tex] 90°
[tex]\angle s + \angle T < \angle 90[/tex]
[tex]\angle R > \angle T[/tex]
[tex]\angle R > \angle S[/tex] Answer
Answer:<R > 90°, <S + <R < 90°, <R > <T, <R > <S
Step-by-step explanation: