Answer:
Energy of photon, [tex]E=8.64\times 10^{-19}\ J[/tex]
Explanation:
It is given that,
Wavelength of photon, [tex]\lambda=2.29\times 10^{-7}\ m[/tex]
It strikes a mercury atom in the ground state. We have to find the energy of this photon. It can be calculated using below relation as :
[tex]E=\dfrac{hc}{\lambda}[/tex]
Where
h is the Planck's constant
c is the speed of light
So, [tex]E=\dfrac{6.6\times 10^{-34}\ J-s\times 3\times 10^8\ m/s}{2.29\times 10^{-7}\ m}[/tex]
[tex]E=8.64\times 10^{-19}\ J[/tex]
Hence, the above value is the energy of this photon.
