Question

Which equations represent the line that is parallel to 3x - 4y = 7 and passes through the point (-4,-2)? Select two
options.
y=-3x+1
3x - 4y = -4
4x - 3y = -3
Dy-2=-2(x-4)
y+2 = (x + 4)

Answer 1

Answer:

The equation of another line with given points and parallel to the first line is 3X - 4Y = - 4    

Step-by-step explanation:

Given as ,

The equation of one line is 3x - 4y = 7

Or, 4y = 3x - 7

Or,  y = $\frac{3}{4}$x - $\frac{7}{4}$

This line is in the form of y = mx + c

So, slop of this line is ( m 1 ) = $\frac{3}{4}$

Now the another line is parallel to this line ,

So, for parallel line condition, slop are equal

i.e (m 1) = ( m 2)              , Let (m 2) is the slop of another line .

So , (m1 ) = (m2) = $\frac{3}{4}$

Again, the another line with slop (m2) passes through points ( - 4 , - 2)

So , equation of another line is

Y - y1 = (m2) (X - x1)

Or, Y + 2 = $\frac{3}{4}$ + (x + 4 )

Or, 3X - 4Y = - 4

Hence the equation of another line with given points and parallel to the first line is 3X - 4Y = - 4    Answer

Answer 2

Answer:

3x-4y=-4 and y+2= 3/4 (xt4)

Step-by-step explanation:

b and e