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I have 3 questions for math

1. Two lines have the given equations. Use the Linear Combination Method to solve.

2x-y=1

3x-y=-6


2. Solve the system of equations using the Substitution Method


4x+2y = 10

y = 4x + 2


3. Solve the system of equations using any method


6x – y = 2

y = 3x + 4

WITH WORK PLEASE

Respuesta :

Answer:

Step-by-step explanation:

1) 2x -y = 1 -------1

3x - y = -6 ------2

Subtract eqn 2 from eqn 1

-x = 1--6 = 7

x = -7

Put x= -7 in eqn 1

2*-7-y = 1

-14-y = 1

- y = 15

y = -15

2) 4x +2y = 10------1

y = 4x + 2--------2

Put eqn 2 in eqn 1

4x + 2 ( 4x+ 2) = 10

4x + 8x + 4 = 10

12x = 6

x = 6/12 = 1/2

Put x = 1/2 in eqn 2

y = 4* 1/2 + 2= 2 + 2

= 4

3) 6x - y = 2------1

y = 3x + 4---------2

Put eqn 2 in eqn 1

6x - (3x +4) = 2

6x - 3x - 4 = 2

3x = 6

x = 2

y = 3*2 + 4 = 6 + 4

= 10