Answer:
mass of SiC at 95.2 % efficiency = 3.67 g
Explanation:
given data
mass of silicon carbide = 5.575
mas of silicon dioxide = ?
efficiency = 95.2%
balanced chemical equation
SiO₂ + 3C → SiC + 2CO
The mole ration of SiO2 and SiC = 1 : 1
First we will find out number of moles of SiO₂ and SiC
As we know that:
number of moles = mass / molar mass
number of moles of SiO₂ = 5.75 / 60.08
number of moles of SiO₂ = 0.096 mol
As the mole ration of SiO₂ and SiC = 1 : 1
so number of moles of SiC = 0.096 / 1
number of moles of SiC = 0.096
Now we find the mass of SiC
mass of SiC = moles × molar mass
mass of SiC = 0.096 mol × 40.11 g/mol
mass of SiC = 3.85 g
3.85 g SiC will produse when there is 100% effeciency
when the reaction is 95.2 % efficient mass of SiC will be:
mass of SiC at 95.2 % efficiency = (3.85 / 100) × 95.2
mass of SiC at 95.2 % efficiency = 0.0385 × 95.2
mass of SiC at 95.2 % efficiency = 3.67 g
