Question

1. TRIATHLON The course for a local
triathlon has the shape of a right triangle.
The legs of the triangle consist of a 4-mile
swim and a 11 mile run. The hypotenuse of
the triangle is the biking portion of the
event. How far is the biking part of the
triathlon? Round to the nearest tenth if
necessary.

Answer 1

The biking portion of the triathlon is 11.7 miles far

Step-by-step explanation:

Let us revise the relation between the two legs of a right triangle and

the hypotenuse

Hypotenuse = $\sqrt{(leg_{1})^{2}+(leg_{2})^{2}}$

To find the length of the hypotenuse

1. Square the length of each leg

2. Add the squares of the legs

3. Find the square root of the sum

∵ The legs of the triangle consist of a 4 mile  swim and a 11 mile run

∴ $leg_{1}$ = 4

∴ $leg_{2}$ = 11

∵ ( $leg_{1}$ )² = (4)² = 16

∵ ( $leg_{2}$ )² = (11)² = 121

∴ ( $leg_{1}$ )² + ( $leg_{2}$ )² = 16 + 121 = 137

∵ The hypotenuse of  the triangle is the biking portion of the  event

∵ Hypotenuse = $\sqrt{(leg_{1})^{2}+(leg_{2})^{2}}$

∴ Hypotenuse = $\sqrt{137}$ = 11.7

The biking portion of the triathlon is 11.7 miles far

Learn more:

You can learn more about Pythagoras Theorem in brainly.com/question/1238144

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