Question

If T = 10x^2/y, then log T is equivalent to
(1 + 2log x) – log y
log(1 + 2x) – log y
(1 - 2log x) + log y
2(1 - log x) + log y

Answer 1

logT = 1 + 2log(x) - log(y)

Step-by-step explanation:

   Given $T=\frac{10x^{2} }{y}$.

We need to evaluate $logT$. Let us apply logarithm on both sides of the above equation.

$logT=log(\frac{10x^{2} }{y})$

We know that $log(ab)=log(a)+log(b)$ and $log(\frac{a}{b})=log(a)-log(b)$, $log(a^{b})=(b)log(a)$.

Hence, $logT=log10+log(x^{2})-log(y)$

∴ $logT=1+2log(x)-log(y)$