Question

An electron in a mercury atom changes from energy level b to a higher energy level when the
atom absorbs a single photon with an energy of 3.06 electronvolts.

Determine the letter that identifies the energy level to which the electron jumped when the mercury
atom absorbed the photon.

Answer 1

The energy is 3.06 electron volts,  E = 3.06eV

1eV = 1.6 * 10^-19 J

3.06 eV = 3.06* 1.6 * 10^-19 J = 4.896 * 10^-19 J

Answer 2

The letter that identifies the energy level to which the electron jumped when the mercury atom absorbed the photon could be L or M.

What is energy level?

Energy levels or electron shells are fixed distances from the nucleus of an atom where electrons may be found.

Letter that identifies the energy level of an atom

A single capital letter K is for the lowest energy level, and capital letters like L and M are used for energy levels further from the nucleus.

Thus, the letter that identifies the energy level to which the electron jumped when the mercury atom absorbed the photon could be L or M.

atom absorbed the photon.

Learn more about energy level here: https://brainly.com/question/14287666

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