Question

8. Both figures have the same perimeter. Find
the measure of each side and the perimeter.
x + 20
x + 55
x + 15
x + 50

Answer 1

The sides are:

A=135

B=95

C=130

L=100

W=20

And the perimeter is: 360

Further explanation:

Given that both figures have same parameter

Let P1 be the perimeter of the triangle and P2 be the perimeter of the rectangle

Then

P1=P2

Let the sides of triangle be

A = x+55

B= x+15

C = x+50

and

Sides of rectangle be

L = x+20

W = x

$If\\P_1=P_2\\A+B+C=2L+2W\\(x+55)+(x+15)+(x+50) = 2(x+20)+2x\\x+55+x+15+x+50=2x+40+2x\\3x+120=4x+40\\3x-4x=-120+40\\-x=-80\\x=80\\Now\\A=x+55=80+55=135\\B=x+15=80+15=95\\C=x+50=80+50=130\\L=x+20=80+20=100\\W=x=20\\Now\ we\ have\ to\ calculate\ perimeter\\P_1=A+B+C\\=135+95+130\\=360\\P_2=2L+2W\\=2(100)+2(80)\\=200+160\\=360$

The sides are:

A=135

B=95

C=130

L=100

W=20

And the perimeter is: 360

Keywords: Perimeter, rectangle, triangle

Learn more about perimeter at:

• brainly.com/question/10772025
• brainly.com/question/10879401

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