Answer:
The correct answer is B
Explanation:
For this exercise we must use the definition of the index of refraction
n = c / v
Where n is the index of refraction, c the speed of light in a vacuum and v the speed of light in the material medium.
v = c / n
As light travels at constant speed, we can use the equations of uniform motion
v = d / t
c / n = d / t
t = d n / c
Let's calculate the travel time for the vacuum, where the refractive index is one (n = 1)
d = 1.5 108 km (1000m / 1 km) = 1.5 10¹¹ m
t = 1.5 10¹¹ 1/3 10⁸
t1 = 5 10² s (1min / 60s) = 8.33 min
Now let's calculate the time for water n = 1,297
t2 = 1.5 10¹¹ 1,297 / 3 10⁸
t2 = 6,485 10² s = 10,808 min
The time difference is the subtraction of these two values
Δt = t2-t1
Δt = 10,808 -500
Δt = 2,478 min
The correct answer is B