Answer:
The probability that a freshman prefer cheese toppings is 0.241
Step-by-step explanation:
Probability of any event E = [tex]\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}[/tex]
Here, let E : Event of choosing cheese toppings
So, the number of favorable outcomes = 14
Total number of outcomes = 58
So, [tex]P(E) = \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}[/tex]
or, P(E) = [tex]\frac{14}{58} = 0.241379[/tex]
So,the probability that a freshman prefer cheese toppings is 0.241379
Rounding of 0.241379 to the nearest thousandth, we get
Here , in 0.241379 thousandth digit is 3, and 3 < 5,
so the value of P(E) = 0.241