Total freshman = 58. Number of freshman who prefer cheese toppings= 14. Determined the probability that a freshman prefer cheese toppings. Round to the nearest thousandth

Respuesta :

Answer:

The probability that a freshman prefer cheese toppings  is   0.241

Step-by-step explanation:

Probability of any event E =  [tex]\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}[/tex]

Here, let E   :  Event of choosing cheese toppings

So, the number of favorable outcomes = 14

Total number of outcomes = 58

So, [tex]P(E) =  \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}[/tex]

or, P(E) = [tex]\frac{14}{58} = 0.241379[/tex]

So,the probability that a freshman prefer cheese toppings  is   0.241379

Rounding of 0.241379  to the nearest thousandth, we get

Here , in 0.241379 thousandth digit is 3, and 3 < 5,

so the value of P(E) = 0.241