Question

If a rocket transfers 2,500,000 MJ of energy when it takes off, how much work is done?

Answer 1

Answer:

2,500,000 MJ ($2.5\cdot 10^6 J$)

Explanation:

According to the work-energy theorem:

The work done on an object is equal to the amount of energy transferred

In this problem, the energy transferred by the rocket is

$E=2,500,000 MJ=2.5\cdot 10^6 J$

Therefore, the work done must be equal to the energy transferred, therefore:

$W=E=2.5\cdot 10^6 J$