Question

A company is to hire two new employees. They have prepared a final list of sixteen candidates, all of whom are equally qualified. Of these sixteen candidates, eleven are women. If the company decides to select two persons randomly from these sixteen candidates, what is the probability that both of them are men? Round your answer to four decimal places.

Answer 1

Answer:

0.0654

Step-by-step explanation:

We are given that

Total number of candidates=16

Total number of women candidates=11

Total number of men candidates=16-11=5

If the company decides to select two persons randomly from these 16 candidates.We have to find the probability that both of them are men.

Probability=$P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of cases}$

Therefore, the probability that both of them are men=$\frac{5}{18}\times \frac{4}{17}=\frac{20}{306}$

Hence, the probability that both selected candidates are men=0.0654