Question

A gas Syringe contains 42.3 milliliters of a gas at 98.15°C. Determine the volume that the gas will occupy if the temperature is decreased to -18.50°C.

Answer 1

V₁ = 42.3 mL

T₁ ( K ) = 98.15ºC + 273 = 371.15 K

V₂ = ?

T₂ ( K) = -18.50ºC + 273 = 254.5 K

V₁ / T₁  = V₂ / T₂

42.3 / 371.15 =  V₂ / 254.5

371.15 x V₂ = 42.3 x  254.5

371.15 x V₂ = 10765.35

V₂ = 10765.35 / 371.15

V₂ = 29.00 mL

hope this helps!

Answer 2

The volume that the gas will occupy is "29.00 mL".

According to the question,

Volume,

• $V_1 = 42.3 \ mL$
• $V_2 = ?$

Temperature,

• $T_1 = 98.15^{\circ} C$

             $= 371.15 \ K$

• $T_2 = -18.50^{\circ} C$

             $= 254.5 \ K$

As we know the relation,

→ $\frac{V_1}{T_1} = \frac{V_2}{T_2}$

or,

→ $V_2 = \frac{V_1\times T_2}{T_1}$

By substituting the values, we get

→      $= \frac{41.3\times 254.5}{371.15}$

→      $= \frac{10765.35}{371.15}$

→      $= 29.00 \ mL$

Thus the above answer is right.  

Learn more:

https://brainly.com/question/22590663