Answer:
Step-by-step explanation:
Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42
Let X be the no of passengers who report
X is N(132, 42)
Or Z is [tex]\frac{x-132}{42}[/tex]
a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.
the probability that the demand will exceed the capacity of this airplane
=[tex]P(X>183) = P(Z>1.21) =[/tex]
[tex]=0.5-0.3869\\=0.1131[/tex]
b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers
=[tex]P(80\leq x\leq 200)\\= P(-1.23\leq z\leq 1.62)\\[/tex]
=0.4474+0.3907
=0.8381
c) the probability that the demand for this flight will be less than 100 passengers
[tex]=P(x<100)\\=P(z<-0.76)\\=0.5-0.2764\\=0.2236[/tex]
d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers
=[tex]P(Z>c)=0.03\\c=1.88\\X=132+1.88(42)\\=210.96[/tex]
e) 79th percentile of this distribution
=[tex]132+0.81(42)\\= 166.02[/tex]