Respuesta :

Answer:

[tex]12.5 x^{10}[/tex]  number of bacteria

Step-by-step explanation:

given as :

The Number of Bacteria in 2 L of water = [tex]5 x^{10}[/tex]

∵   2 L of water have = [tex]5 x^{10}[/tex] number of bacteria

So  1 L of water have = [tex]\frac{5 x^{10}}{2}[/tex]  number of bacteria

∴    5 L of water have = [tex]\frac{5 x^{10}}{2}[/tex] × 5 number of bacteria

                                    = [tex]12.5 x^{10}[/tex]  number of bacteria

Hence in 5 L of water , [tex]12.5 x^{10}[/tex]  number of bacteria available   Answer

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