Answer:
[tex]12.5 x^{10}[/tex] number of bacteria
Step-by-step explanation:
given as :
The Number of Bacteria in 2 L of water = [tex]5 x^{10}[/tex]
∵ 2 L of water have = [tex]5 x^{10}[/tex] number of bacteria
So 1 L of water have = [tex]\frac{5 x^{10}}{2}[/tex] number of bacteria
∴ 5 L of water have = [tex]\frac{5 x^{10}}{2}[/tex] × 5 number of bacteria
= [tex]12.5 x^{10}[/tex] number of bacteria
Hence in 5 L of water , [tex]12.5 x^{10}[/tex] number of bacteria available Answer
